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3922:A simple stone game

题目描述
After he has learned how to play Nim game, Mike begins to try another stone game which seems much easier.

The game goes like this: Two players start the game with a pile of n stones. They take stones from the pile in turn and every time they take at least one stone. The one who goes first can take at most n-1 stones for his first move. From then on a player can take at most k times as many stones as his opponent has taken last time. For example, if one player take m stones in his turn, then the other player can take at most k * m stones next time. The player who takes the last stone wins the game. Suppose that those two players always take the best moves and never make mistakes, your job is to find out who will definitely win the game.
输入解释
The first line contains a integer t, indicating that there are t test cases following.(t<=20).
Each test case is a line consisting of two integer n and k.(2<=n<=108,1<=k<=105).
输出解释
For each test case, output one line starting with “Case N: ”, N is the case number. And then, if the first player can ensure a winning, print the minimum number of stones he should take in his first turn. Otherwise, print "lose". Please note that there is a blank following the colon.
输入样例
5 
16 1 
11 1 
32 2 
34 2 
19 3
输出样例
Case 1: lose
Case 2: 1
Case 3: 3
Case 4: lose
Case 5: 4
提示
When k = 1, the first player will definitely lose if the initial amount of stones is in the set {2, 4, 8, 16, 32, ...}. Let's call this kind of set “first-player-lose set”.

When k = 2, the first-player-lose set is {2, 3, 5, 8, 13, 21, 34, 57 ...} , which happens to be the Fibonacci sequence starting from 2.

该题目是Virtual Judge题目,来自 北京大学POJ

题目来源 Beijing 2008

源链接: POJ-3922

最后修改于 2020-10-29T07:15:37+00:00 由爬虫自动更新

共提交 0

通过率 --%
时间上限 内存上限
1000 65536