当前你的浏览器版本过低,网站已在兼容模式下运行,兼容模式仅提供最小功能支持,网站样式可能显示不正常。
请尽快升级浏览器以体验网站在线编辑、在线运行等功能。
In the Cartesian plane, there are n (odd) distinct lines fi(x) = ai + xbi (i = 1, 2, …, n). For each x, F(x) denotes the median of {f1(x), f2(x), ..., fn(x)}. You are required to find the solution space of the equation F(x) = 0.
The input contains multiple test cases. Each test case have n + 1 lines the first one of which contains n (1 < n < 105 and odd). Then n lines follow, each of which contains two integers ai and bi (|ai| ≤ 108, 0 ≤ bi < 108). A zero follows the last test case.
+inf
” and “-inf
” are used to represent positive and negative infinities. The solution space will form at most one interval in this problem. If the solution space is empty, just output “-1
”.3 0 0 1 0 0 1 3 0 0 1 2 1 1 3 1 0 2 0 3 0 3 1 1 1 2 1 3 3 0 0 1 0 -1 0 0
(-inf,0.00] [-1.00,-0.50] -1 [-0.50,-0.50] (-inf,+inf)
Be cautious about outputting “-0.00
”.
Illustration of the second test case in the sample input:
时间上限 | 内存上限 |
6000 | 131072 |