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2381:Random Gap

题目描述
The pseudo-random number genegators (or RNGs for short) are widely used in statistical calculations. One of the simplest and ubiquitious is the linear congruence RNG, that calculates the n-th random number Rn as Rn = (aRn - 1 + c) mod m, where a, c and m are constants. For example, the sequence for a = 15, c = 7, m = 100 and starting value R0 = 1 is 1, 22, 37, 62, 37, 62, ...

Linear RNG is very fast, and can yield surprisinly good sequence of random numbers, given the right choice of constants. There are various measures of RNG quality, and your task is to calculate one of them, namely the longest gap between members of the sequence. More precisely, given the values of a, c, m, and R0, find such two elements Ri < Rj that:
  1. there are no other Rk that Ri ≤ Rk ≤ Rj,
  2. the difference Rj − Ri is maximal.
输入解释
Input contains integer numbers a c m R0.
0 ≤ a, c, R0 ≤ 107, 1 ≤ m ≤ 16000000, am + c < 232.
输出解释
Output should contain the single number -- the maximal difference found.
输入样例
15 7 100 1
输出样例
25

该题目是Virtual Judge题目,来自 北京大学POJ

源链接: POJ-2381

最后修改于 2020-10-29T06:31:05+00:00 由爬虫自动更新

共提交 0

通过率 --%
时间上限 内存上限
3000 65536