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2244:Eeny Meeny Moo

题目描述
Surely you have made the experience that when too many people use the Internet simultaneously, the net becomes very, very slow.
To put an end to this problem, the University of Ulm has developed a contingency scheme for times of peak load to cut off net access for some cities of the country in a systematic, totally fair manner. Germany's cities were enumerated randomly from 1 to n. Freiburg was number 1, Ulm was number 2, Karlsruhe was number 3, and so on in a purely random order.
Then a number m would be picked at random, and Internet access would first be cut off in city 1 (clearly the fairest starting point) and then in every mth city after that, wrapping around to 1 after n, and ignoring cities already cut off. For example, if n=17 and m=5, net access would be cut off to the cities in the order [1,6,11,16,5,12,2,9,17,10,4,15,14,3,8,13,7]. The problem is that it is clearly fairest to cut off Ulm last (after all, this is where the best programmers come from), so for a given n, the random number m needs to be carefully chosen so that city 2 is the last city selected.

Your job is to write a program that will read in a number of cities n and then determine the smallest integer m that will ensure that Ulm can surf the net while the rest of the country is cut off.
输入解释
The input will contain one or more lines, each line containing one integer n with 3 <= n < 150, representing the number of cities in the country.
Input is terminated by a value of zero (0) for n.
输出解释
For each line of the input, print one line containing the integer m fulfilling the requirement specified above.
输入样例
3
4
5
6
7
8
9
10
11
12
0
输出样例
2
5
2
4
3
11
2
3
8
16

该题目是Virtual Judge题目,来自 北京大学POJ

题目来源 Ulm Local 1996

源链接: POJ-2244

最后修改于 2020-10-29T06:27:25+00:00 由爬虫自动更新

共提交 0

通过率 --%
时间上限 内存上限
1000 65536