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1690:(Your)((Term)((Project)))

题目描述
You have typed the report of your term project in your personal computer. There are several one line arithmetic expressions in your report. There is no redundant parentheses in the expressions (omitting a pair of redundant matching parentheses does not change the value of the expression). In your absence, your little brother inserts some redundant matching parentheses in the expressions of your report. Assume that the expressions remain syntactically correct and evaluate to their original value (the value before inserting redundant parentheses). To restore your report to its original form, you are to write a program to omit all redundant parentheses.
To make life easier, consider the following simplifying assumptions:
  1. The input file contains a number of expressions, each in one separate line.
  2. Variables in the expressions are only single uppercase letters.
  3. Operators in the expressions are only binary '+' and binary '-'.

Note that the only transformation allowed is omission of redundant parentheses, and no algebraic simplification is allowed.
输入解释
The input consists of several test cases. The first line of the file contains a single number M, which is the number of test cases (1 <= M <= 10). Each of the following M lines, is exactly one correct expression. There may be arbitrarily space characters in each line. The length of each line (including spaces) is at most 255 characters.
输出解释
The output for each test case is the same expression without redundant parentheses. Notice that the order of operands in an input expression and its corresponding output should be the same. Each output expression must be on a separate line. Space characters should be omitted in the output expressions.
输入样例
3
(A-B + C) - (A+(B - C)) - (C-(D- E) )
  ((A)-( (B)))
A-(B+C)
输出样例
A-B+C-(A+B-C)-(C-(D-E))
A-B
A-(B+C)

该题目是Virtual Judge题目,来自 北京大学POJ

题目来源 Tehran 1999

源链接: POJ-1690

最后修改于 2020-10-29T06:11:13+00:00 由爬虫自动更新

共提交 0

通过率 --%
时间上限 内存上限
1000 10000