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6430:Problem E. TeaTree

题目描述
Recently, TeaTree acquire new knoledge gcd (Greatest Common Divisor), now she want to test you.
As we know, TeaTree is a tree and her root is node 1, she have n nodes and n-1 edge, for each node i, it has it’s value v[i].
For every two nodes i and j (i is not equal to j), they will tell their Lowest Common Ancestors (LCA) a number : gcd(v[i],v[j]).
For each node, you have to calculate the max number that it heard. some definition:
In graph theory and computer science, the lowest common ancestor (LCA) of two nodes u and v in a tree is the lowest (deepest) node that has both u and v as descendants, where we define each node to be a descendant of itself.
输入解释
On the first line, there is a positive integer n, which describe the number of nodes.
Next line there are n-1 positive integers f[2] ,f[3], …, f[n], f[i] describe the father of node i on tree.
Next line there are n positive integers v[2] ,v[3], …, v[n], v[i] describe the value of node i.
n<=100000, f[i]<i, v[i]<=100000
输出解释
Your output should include n lines, for i-th line, output the max number that node i heard.
For the nodes who heard nothing, output -1.
输入样例
4
1 1 3
4 1 6 9
输出样例
2
-1
3
-1
来自杭电HDUOJ的附加信息
Recommend chendu

该题目是Virtual Judge题目,来自 杭电HDUOJ

源链接: HDU-6430

最后修改于 2020-10-25T23:31:16+00:00 由爬虫自动更新

共提交 0

通过率 --%
时间上限 内存上限
8000/4000MS(Java/Others) 524288/524288K(Java/Others)