Line Graph $L(G)$ can be considered as an operator on an undirected graph $G$ just like Complementary Graph and Dual Graph.
Rikka generalizes Line Graph to edge-weighted undirected graphs. For a graph $G=\langle V,E\rangle$, $L(G)$ is still an edge-weighted undirected graph which is constructed in the following way:
1. $L(G)$ has $|E|$ vertices and the $i$th vertex corresponds to the $i$th edge in $G$.
2. There is an edge between $i,j$ in $L(G)$ if and only if edge $i$ and $j$ have at least one common vertices in $G$. And the edge weight is equal to the sum of the weights of edge $i$ and $j$ in $G$.
For example, in the following picture, the right graph is the line graph of the left one. Vertex $1,2,3,4$ in $L(G)$ correspond to edge $(1,2),(1,4),(1,3),(3,4)$ in $G$. And if all edges in the left graph have weight $1$, the edges in the right graph will have weight $2$.

Now, Rikka has an edge-weighted tree $T$ with $n$ vertices. And she constructs a graph $G=L(L(T))$. It is clear that $G$ is connected.
Let $d(i,j)$ be the length of the shortest path between vertex $i,j$ in $G$(the length of each edge is equal to the weight), $m$ be the number of vertices in $G$, Rikka wants you to calculate $\sum_{i=1}^m \sum_{j=i+1}^m d(i,j)$.