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6047:Maximum Sequence

题目描述
Steph is extremely obsessed with “sequence problems” that are usually seen on magazines: Given the sequence 11, 23, 30, 35, what is the next number? Steph always finds them too easy for such a genius like himself until one day Klay comes up with a problem and ask him about it.

Given two integer sequences {ai} and {bi} with the same length n, you are to find the next n numbers of {ai}: $a_{n+1}…a_{2n}$. Just like always, there are some restrictions on $a_{n+1}…a_{2n}$: for each number $a_i$, you must choose a number $b_k$ from {bi}, and it must satisfy $a_i$≤max{$a_j$-j│$b_k$≤j<i}, and any $b_k$ can’t be chosen more than once. Apparently, there are a great many possibilities, so you are required to find max{$\sum_{n+1}^{2n}a_i$} modulo $10^9$+7 .

Now Steph finds it too hard to solve the problem, please help him.
输入解释
The input contains no more than 20 test cases.
For each test case, the first line consists of one integer n. The next line consists of n integers representing {ai}. And the third line consists of n integers representing {bi}.
1≤n≤250000, n≤a_i≤1500000, 1≤b_i≤n.
输出解释
For each test case, print the answer on one line: max{$\sum_{n+1}^{2n}a_i$} modulo $10^9$+7。
输入样例
4
8 11 8 5
3 1 4 2
输出样例
27
提示
For the first sample:
1. Choose 2 from {bi}, then a_2…a_4 are available for a_5, and you can let a_5=a_2-2=9; 
2. Choose 1 from {bi}, then a_1…a_5 are available for a_6, and you can let a_6=a_2-2=9;
来自杭电HDUOJ的附加信息
Recommend liuyiding

该题目是Virtual Judge题目,来自 杭电HDUOJ

源链接: HDU-6047

最后修改于 2020-10-25T23:27:50+00:00 由爬虫自动更新

共提交 0

通过率 --%
时间上限 内存上限
4000/2000MS(Java/Others) 32768/32768K(Java/Others)