当前你的浏览器版本过低，网站已在兼容模式下运行，兼容模式仅提供最小功能支持，网站样式可能显示不正常。
请尽快升级浏览器以体验网站在线编辑、在线运行等功能。

建议使用的浏览器：

谷歌Chrome 火狐Firefox Opera浏览器 微软Edge浏览器 QQ浏览器 360浏览器 傲游浏览器

5775：Bubble Sort

题目描述
P is a permutation of the integers from 1 to N(index starting from 1).
Here is the code of Bubble Sort in C++.

for(int i=1;i<=N;++i)
    for(int j=N,t;j>i;—j)
        if(P[j-1] > P[j])
            t=P[j],P[j]=P[j-1],P[j-1]=t;

After the sort, the array is in increasing order. ?? wants to know the absolute values of difference of rightmost place and leftmost place for every number it reached.
输入解释
The first line of the input gives the number of test cases T; T test cases follow.
Each consists of one line with one integer N, followed by another line with a permutation of the integers from 1 to N, inclusive.

limits
T <= 20
1 <= N <= 100000
N is larger than 10000 in only one case.
输出解释
For each test case output “Case #x: y1 y2 … yN” (without quotes), where x is the test case number (starting from 1), and yi is the difference of rightmost place and leftmost place of number i.
输入样例 
2
3
3 1 2
3
1 2 3
输出样例 
Case #1: 1 1 2
Case #2: 0 0 0
提示
In first case, (3, 1, 2) -> (3, 1, 2) -> (1, 3, 2) -> (1, 2, 3)
the leftmost place and rightmost place of 1 is 1 and 2, 2 is 2 and 3, 3 is 1 and 3
In second case, the array has already in increasing order. So the answer of every number is 0.
来自杭电HDUOJ的附加信息
Author FZU
Recommend wange2014
该题目是Virtual Judge题目，来自 杭电HDUOJ
题目来源 2016 Multi-University Training Contest 4
源链接： HDU-5775
最后修改于 2020-10-25T23:25:33+00:00 由爬虫自动更新
共提交 0 次
通过率 --%
时间上限 内存上限
2000/1000MS(Java/Others) 65536/65536K(Java/Others)