当前你的浏览器版本过低,网站已在兼容模式下运行,兼容模式仅提供最小功能支持,网站样式可能显示不正常。
请尽快升级浏览器以体验网站在线编辑、在线运行等功能。

建议使用的浏览器:

谷歌Chrome 火狐Firefox Opera浏览器 微软Edge浏览器 QQ浏览器 360浏览器 傲游浏览器

4606:Occupy Cities

题目描述
The Star Wars is coming to an end as the Apple Planet is beaten by the Banana Planet. Captain Chen, the glorious leader of the Army of Banana Planet, has drawn up a plan to occupy all the cities on the Apple Planet. The Army of Banana Planet totally has P soldiers, and thus, Captain Chen can only conduct at most P soldiers to occupy the cities.
The cities on the planet can be regarded as points on a 2D plane. What's more, there are some barriers on the planet, which can be seen as segments on the plane. When a soldier moves from city to city, he's not allowed to cross or touch the barriers. However, the soldiers are smart enough to go along the shortest paths between cities.
But these soldiers are just soldiers, whereupon they also need food to replenish their energy. A soldier needs one unit of food to move one unit of distance forward. Fortunately, all the cities have sufficient food supplies. When a soldier steps in a city, he will fill up his food bag. Invaders as they are, the soldiers will burn up all the food after filling his bag. And thus, each city can supply only one soldier.
When a soldier steps in a city, this city is occupied by the Army of Banana Planet immediately. Soldiers can also just pass by a city but not step in. In this case, this city is not occupied yet, and the food in the city would not be burned.
Captain Chen has an occupying schedule for his soldiers. If city A is arranged before city B on the schedule, city A must be occupied before city B. All the soldiers will strictly follow this schedule. During the occupying process, soldiers can be air-dropped to any positions on the plane as needed. After a soldier lands on the ground, he can only move on foot, and replenish his energy by the food in his bag. Note that their bags are full of food initially, and all bags have the same volume for soldiers.
You, the logistics minister of the army, are required to help the Captain to cut down the cost and determine the minimal volume of all P soldiers' food bags to finish occupying. All the requirements above should be fulfilled for sure.
输入解释
The first line contains an integer T(T≤50), indictaing the number of test cases.
Each test case begins with three integers n(0<n≤100), m(0≤m≤100) and p(0<p≤100), which respectively denotes the number of cities, barriers and soldiers.
The following n lines describe the cities' coordinates (x_i,y_i).
The next m lines, each with two pairs of integers (sxi,syi) and (exi,eyi), describe the two endpoints of each barrier.
The last line of each test case consists of n integers, describing the occupying schedule in order.
All the coordinates range from -10000 to 10000, and cities are labeled from 1 to n. You may assume that any two barriers will not have common points and cities will not be built on barriers.
输出解释
For each test case, output the minimal volume of soldiers' food bag, in accuracy of two decimal places. The answers should be printed one per line.
输入样例
2

2 1 1
0 0
2 0
1 1 1 -1
2 1

4 2 2
0 1
5 1
8 0
1 -1
0 0 2 0
6 0 6 3
1 2 3 4
输出样例
2.83
3.41
提示
For the second sample case, the best strategy is:
step 1: air-drop soldier 1 to city 1, city 1 occupied;
step 2: air-drop soldier 2 to city 2, city 2 occupied;
step 3: soldier 2 moves from city 2 to city 3, city 3 occupied, and 3.41 units of food needed;
step 4: soldier 1 moves from city 1 to city 4, city 4 occupied, and 2.41 units food needed.
Therefore, the minimal volume of bags is 3.41.
来自杭电HDUOJ的附加信息
Recommend liuyiding

该题目是Virtual Judge题目,来自 杭电HDUOJ

源链接: HDU-4606

最后修改于 2020-10-25T23:15:05+00:00 由爬虫自动更新

共提交 0

通过率 --%
时间上限 内存上限
10000/5000MS(Java/Others) 32768/32768K(Java/Others)