当前你的浏览器版本过低,网站已在兼容模式下运行,兼容模式仅提供最小功能支持,网站样式可能显示不正常。
请尽快升级浏览器以体验网站在线编辑、在线运行等功能。

建议使用的浏览器:

谷歌Chrome 火狐Firefox Opera浏览器 微软Edge浏览器 QQ浏览器 360浏览器 傲游浏览器

4433:locker

题目描述
A password locker with N digits, each digit can be rotated to 0-9 circularly.
You can rotate 1-3 consecutive digits up or down in one step.
For examples:
567890 -> 567901 (by rotating the last 3 digits up)
000000 -> 000900 (by rotating the 4th digit down)
Given the current state and the secret password, what is the minimum amount of steps you have to rotate the locker in order to get from current state to the secret password?
输入解释
Multiple (less than 50) cases, process to EOF.
For each case, two strings with equal length (≤ 1000) consists of only digits are given, representing the current state and the secret password, respectively.
输出解释
For each case, output one integer, the minimum amount of steps from the current state to the secret password.
输入样例
111111 222222
896521 183995
输出样例
2
12
来自杭电HDUOJ的附加信息
Recommend zhoujiaqi2010

该题目是Virtual Judge题目,来自 杭电HDUOJ

源链接: HDU-4433

最后修改于 2020-10-25T23:13:28+00:00 由爬虫自动更新

共提交 0

通过率 --%
时间上限 内存上限
6000/3000MS(Java/Others) 32768/32768K(Java/Others)