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3 0 0 4 2 1
Case 1: 0.5000 Case 2: 0.5000
For example as the sample test one, there are three balls in the bag. The possibilities of the four possible situations are all 0.25. If there are no red balls in the bag, the possibility of the next ball are red is 0. If there is one red ball in the bag, the possibility is 1/3. If there are two red balls, the possibility is 2/3. Finally if all balls are red, the possibility is 1. So the answer is 0*(1/4)+(1/3)*(1/4)+(2/3)*(1/4)+1*(1/4)=0.5.
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时间上限 | 内存上限 |
2000/1000MS(Java/Others) | 32768/32768K(Java/Others) |