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2886:Lou 1 Zhuang

题目描述
All members of Hulafly love playing the famous network game called 'Lou 1 Zhuang' so much that Super Da Lord got mad with them. So he thought over and over and finally came up with a good idea to stop them. He consulted an ACM master and asked for the hardest problem ever in the world. Hulafly must solve this problem in order to get permission of playing 'Lou 1 Zhuang'. They, however, are so eager to play 'Lou 1 zhuang' and have no interest in this problem at all, so they turn to you for help. You can do this only if you swear that you will never tell Da Lord that you have helped them.

'Lou 1 Zhuang' is a game with only one but a very tall buiding in it and everybody runs a shop in this buiding ---- either a cake shop or a barbershop, each one occupies a whole floor. (Log in at www.xiaonei.com and check details at http://apps.xiaonei.com/soletower/tower.php?origin=2807) Super Da Lord asks that if the buiding is N stories high, how can we devided the floors(or the shops) and multiply the number of floors(or shops) in each part to make the product P as large as possible. Neverthless, Super Da Lord thought that it's still too hard for them, so he gave them some hints, he said:"Go and find the solutoin in 'Lou 1 Zhuang'!"

Given the buidings' height N, you are to find the largest P.
输入解释
The buidings' height N. (1 <= N <= 10^9)

输出解释
The product you've found P (mod 2009).

输入样例
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输出样例
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提示
Hint
You can apply to be huhupao, flytosky and koala's friends at xiaonei.com.
来自杭电HDUOJ的附加信息
Recommend gaojie

该题目是Virtual Judge题目,来自 杭电HDUOJ

源链接: HDU-2886

最后修改于 2020-10-25T22:57:50+00:00 由爬虫自动更新

共提交 0

通过率 --%
时间上限 内存上限
2000/1000MS(Java/Others) 32768/32768K(Java/Others)