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1981:A Special Text Editor

题目描述
After AC all the hardest problems in the world , the ACboy 8006 now has nothing to do . So he develops a special text editor.The text editor is so special that it only supports 3 special operation: "Reverse","Shift" and "Query".

1.The "Reverse" command has 2 parameters A and B.
The format is "R A B". After the command executed, the editor will reverse the substring which is in the string from position A to position B.

2.The "Shift" command also has 2 parameters A and B.
The format is "S A B". After the command executed, the editor will translate every character in the substring which is in the string from positon A to position B to the NEXT character in alphabetic table.In another word, it will translate 'a' to 'b','b' to 'c' ... 'y' to 'z'. Specially it will translate 'z' to 'a'.

3.The "Query" command has only 1 parameter A.
The format is "Q A". When the text editor receives the command,it just reports the character which is in the postion A of the string now.


For example, let's consider the string "abcdefzh" whose length is 8.
After we operate the command "R 2 7", the string will be "azfedcbh".
Then after we operate the command "S 2 3", it will be "aagedcbh".

Now your task is to simulate the process, and output the exact character when you read a "Query" command. Is that easy ? Just come and AC it !
输入解释
The first line of the input contains an integer T which means the number of test cases. Then T test cases follow.
In the first line there are two integers N(0<N<=80000) and C(0<C<=3000) which indicate the length of the string and the number of the commands.
In the second line there is a string whose length is N and which is only consisted of lowercase letters.
Then C lines follow. Each line describes a command in the form of 'Q A' or 'R A B' or 'S A B' (0<A<=B<=N).
输出解释
For each "Query" command, output the character which the text editor reports.
输入样例
1
8 5
abcdefzh
Q 4
R 2 7
Q 3
S 2 3
Q 2
输出样例
d
f
a
来自杭电HDUOJ的附加信息
Author linle
Recommend wangye

该题目是Virtual Judge题目,来自 杭电HDUOJ

源链接: HDU-1981

最后修改于 2020-10-25T22:49:30+00:00 由爬虫自动更新

共提交 0

通过率 --%
时间上限 内存上限
4000/2000MS(Java/Others) 32768/32768K(Java/Others)